File:Rational sequence with 2 accumulation points.pdf
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| Description |
English: Shows the sequence (-1)n·n/(n+1), which has no limit point, but two accumulation points, viz. -1 and +1. |
| Date | |
| Source | Own work |
| Author | Jochen Burghardt |
| Permission (Reusing this file) |
I, the copyright holder of this work, hereby publish it under the following license:    This file is licensed under the Creative Commons Attribution-Share Alike 3.0 Unported license.
|
| Other versions | File:Rational sequence with 2 accumulation points svg.svg |
| LaTeX source code |
|---|
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\end{picture}
\end{document}
|
| C source code to generate sequence members |
|---|
#include <stdio.h>
static inline void prPts(
int n)
{
int i;
int sg;
sg = +1;
for (i=0; i<n; ++i) {
double const v = (double)(i) / (double)(i+1);
printf(" \\textcolor{cSeq}{");
printf("\\put(%10.6f,2){",sg*v*100.0);
printf("\\line(0,-1){2}}}%%\n");
printf("%%\\textcolor{cSqt}{");
printf("\\put(%10.6f,5){",sg*v*100.0);
printf("\\makebox(0,0)[b]{$");
//printf(sg > 0 ? "+" : "-");
printf("\\frac{%d}{%d}$}}}%%\n",i,i+1);
sg = -sg;
}
}
int main(
int argc,
const char * const argv[argc])
{
prPts(1000);
return 0;
}
|
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| Date/Time | Thumbnail | Dimensions | User | Comment | |
|---|---|---|---|---|---|
| current | 19:39, 2 January 2014 |  | 1,356 × 87 (12 KB) | Jochen Burghardt (talk | contribs) | {{Information |Description ={{en|1=(later)}} |Source ={{own}} |Author =Jochen Burghardt |Date =2013-12-30 |Permission = |other_versions = }} |
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- File:Rational sequence with 2 accumulation points .pdf (file redirect)
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