# User talk:Amtiss

Criticism for my pictures is welcome. Ich freue mich über Kritik. Eventuell kann ich Verbesserungsvorschläge sogar umsetzen.

## Image:The Scream.jpg

This image has been deleted. In many countries, including Norway, copyright lasts for the life of the author + 70 years. Since Edvard Munch died in 1944, this work will not be public domain until 2015. Thuresson 06:28, 10 December 2005 (UTC)

Ok that's right, but do you know why the French can use this. Just because they have an other copyright ? Then they could use the original one, with the right colors and not such a ugly version :-). -- Amtiss 22:13, 19 December 2005 (UTC)

## UUE

User Upload Error. Cary "Bastique" Bass parler voir 21:09, 16 April 2006 (UTC)

If you mean Image:Fehler-abschnitt-bearbeiten-unter-text.png then you typed:
{{delete}} - fehler bereits länger bekannt und in bugzilla eingetragen
and: error in displaying text: edit-section-link is under the text. Taken from Wikipedia, while using Mozilla 1.7.12. Cary "Bastique" Bass parler voir 21:14, 16 April 2006 (UTC)
Yes, I meant that. I know that had put the delete tag in the page. I was only interested, also because I did not find something by searching the web. -- Amtiss 18:41, 17 April 2006 (UTC)

## Repoussoir

I put some examples of repoussoir in painting on nl:Repoussoir, maybe you can reproduce something like this with photography. Please note, the repoussoir is usually dark, which is difficult with flashlight on a desktop. Take care. Elly 15:01, 19 June 2006 (UTC)

Well, I wasn't sure, if I really understood what a repoussoir. I've read the German article about, but it's really short, and I tried to improve it. I've got to look whats on my camera. Maybe I find something better. Thanks for your hint. -- 18:11, 19 June 2006 (UTC)
Another try: is this better illustrating a repoussoir ?
This is much better! Elly 19:46, 19 June 2006 (UTC)

## File:Loi de bragg.png

Dein Französisch ist klar. Ich versuche selbst Deutsch zu schreiben ;-)

Was wigtig ist, ist Phasenverschiebung zwischen beide Strahlen, d.h. die Unterschied zwischen Weglänge

${\displaystyle \varphi =2\pi {\frac {\Delta \mathrm {L} }{\lambda }}}$
• konstruktiv : φ = 2kπ ⇒ ΔL = kλ ; n = k ∈ ℕ
• destruktiv : φ = 2(k + 1)π ⇒ ΔL = [(2k+1)/2]λ ; n = k + 0.5, k ∈ ℕ.

Aber n kann negativ sein, destruktiv Interferenz gibt es für höher und niedriger Winkeln.

Cdang (talk) 15:56, 8 June 2009 (UTC)