File:Área y Volumen del Tetraedro Estrellado Davinciano.gif

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Área_y_Volumen_del_Tetraedro_Estrellado_Davinciano.gif ‎(785 × 559 pixels, file size: 857 KB, MIME type: image/gif, looped, 131 frames, 10 s)

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Español: El área de un tetraedro estrellado Davinciano es 12 veces el área de un triángulo regular = 12(0.4330127018922193 L“elevado al cuadrado”) =5,196152422706632 L“elevado al cuadrado”

Atd = área de un tetraedro estrellado Davinciano Atd = 5.196152422706632 L“elevado al cuadrado” = 5.1961 L“elevado al cuadrado” Atd = 5.1961 L“elevado al cuadrado” ¿Cual es el área de un tetraedro estrellado Davinciano? si una de sus aristas intermedias mide 5 Cm. L = 5 Cm, Formula, Atd = 5.1961 L“elevado al cuadrado”. Sustituyendo y resolviendo Atd = 5.1961 L“elevado al cuadrado”. = 5.1961(5 Cm)“elevado al cuadrado”.= 5.1961(25 Cm“elevado al cuadrado”) =129.9025 Cm“elevado al cuadrado” Redondeando Atd =130 Cm “elevado al cuadrado”. El volumen de un tetraedro estrellado Davinciano es 5 veces el volumen de un tetraedro regular. Vtd = 5(0.117776 L“elevado a la 3”) = 0.58888 L“elevado a la 3”. Vtd = volumen de un tetraedro estrellado Davinciano. Vtd = 0.58888 L“elevado a la 3” Cual es el Volumen de un tetraedro estrellado Davinciano, si una de sus aristas intermedias mide 5 Cm. L = 5 Cm, Formula Vtd = 0.58888 L“elevado a la 3”. Sustituyendo y resolviendo: Vtd = 0.58888 L“elevado a la 3” = 0.58888(5 Cm)“elevado a la 3” = 0.58888(125 Cm“elevado a la 3”)= 73.61 Cm“elevado a la 3”.

Vtd = 73.61 Cm“elevado a la 3”.
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Author J.Joel Leonardo

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current02:03, 10 January 2019Thumbnail for version as of 02:03, 10 January 2019785 × 559 (857 KB)J.Joel Leonardo (talk | contribs)User created page with UploadWizard

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