Category:Bertrand's paradox
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problem within the classical interpretation of probability theory: what is the probability that a randomly chosen chord on a circle is longer than a side of an equilateral triangle inscribed in the circle? ![]() Random Endpoints method: Pick 2 random points on the circumference of the circle; draw the chord joining them. To find the probability: rotate the triangle so its vertex coincides with one of the chord endpoints. The chord is longer iff the other chord endpoint lies on the arc between the endpoints of the triangle side opposite the 1st point. So the probability is ⅓. | |||||
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Media in category "Bertrand's paradox"
The following 26 files are in this category, out of 26 total.
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Bertrand1 figure ABC.svg 362 × 362; 3 KB
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Bertrand1-chords.jpg 180 × 181; 16 KB
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Bertrand1-chords.svg 513 × 501; 101 KB
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Bertrand1-figure with letters.png 185 × 185; 14 KB
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Bertrand1-figure.jpeg 170 × 169; 8 KB
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Bertrand1-figure.png 161 × 161; 11 KB
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Bertrand1-figure.svg 322 × 322; 776 bytes
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Bertrand1-scatterplot.jpeg 288 × 288; 17 KB
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Bertrand1-scatterplot.svg 513 × 501; 610 KB
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Bertrand2-chords.jpg 180 × 180; 15 KB
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Bertrand2-chords.svg 513 × 501; 101 KB
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Bertrand2-figure.jpeg 160 × 160; 6 KB
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Bertrand2-figure.png 161 × 161; 11 KB
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Bertrand2-figure.svg 161 × 161; 1 KB
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Bertrand2-scatterplot.jpeg 288 × 288; 16 KB
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Bertrand2-scatterplot.svg 513 × 501; 611 KB
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Bertrand3-chords.jpg 666 × 667; 242 KB
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Bertrand3-chords.svg 513 × 501; 101 KB
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Bertrand3-figure.jpeg 169 × 169; 8 KB
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Bertrand3-figure.png 161 × 161; 12 KB
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Bertrand3-figure.svg 161 × 161; 1 KB
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Bertrand3-Jaynes1.png 409 × 412; 225 KB
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Bertrand3-scatterplot.jpeg 288 × 288; 17 KB
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Bertrand3-scatterplot.svg 513 × 501; 610 KB
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Bertrand3-translate ru.svg 513 × 501; 135 KB
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BertrandReverse.png 616 × 204; 27 KB